A particle is projected from the ground with an initial speed $\upsilon $ at an angle $\theta $ with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is

  • A

    $\frac{\upsilon }{2}\sqrt {1 + 2\,\,{{\cos }^{2\,}}\theta } $

  • B

    $\frac{\upsilon }{2}\sqrt {1 + {{\cos }^{2\,}}\theta } $

  • C

    $\frac{\upsilon }{2}\sqrt {1 + 3\,\,{{\cos }^{2\,}}\theta } $

  • D

    $\upsilon \,\cos \,\theta $

Similar Questions

Match the columns

  Column $-I$
    $R/H_{max}$
  Column $-II$
  Angle of projection $\theta $
   $A.$ $1$    $1.$ ${60^o}$
   $B.$ $4$    $2.$ ${30^o}$
   $C.$ $4\sqrt 3$    $3.$ ${45^o}$
   $D.$ $\frac {4}{\sqrt 3}$    $4.$ $tan^{-1}\,4\,=\,{76^o}$

 

A shell is fired from a fixed artillery gun with an initial speed $u$ such that it hits the target on the ground at a distance $R$ from it. If $t_1$ and $t_2$ are the values of the time taken by it to hit the target in two possible ways, the product $t_1t_2$ is

  • [JEE MAIN 2019]

A projectile crosses two walls of equal height $H$ symmetrically as shown If the horizontal distance between the two walls is $d = 120\,\, m$, then the range of the projectile is ........ $m$

Two stones having different masses $m_1$ and $m_2$ are projected at an angle $\alpha$ and $\left(90^{\circ}-\alpha\right)$ with same speed from same point. The ratio of their maximum heights is

Trajectory of particle in a projectile motion is given as $y=x-\frac{x^2}{80}$. Here, $x$ and $y$ are in metre. For this projectile motion match the following with $g=10\,m / s ^2$.

$Column-I$ $Column-II$
$(A)$ Angle of projection $(p)$ $20\,m$
$(B)$ Angle of velocity with horizontal after $4\,s$ $(q)$ $80\,m$
$(C)$ Maximum height $(r)$ $45^{\circ}$
$(D)$ Horizontal range $(s)$ $\tan ^{-1}\left(\frac{1}{2}\right)$